Sn^+2 (aq) + 2Fe^+3 (aq) --> Sn^+4 (aq) + 2Fe^+2 (aq) Standard E nut = 0.617 V?

Question

What is the value of E when [Sn^+2] and [Fe^+3] are equal to 0.50 M and [Sn^+4] and [Fe^+2] are equal to 0.10 M?

Answer 1

You need a temperature to do this

ΔE = ΔEo - (RT/nF)lnK, where

K = equilibrium constant

R = 8.314 JK-1mol-1

n = number of electrons transferred in the balanced redox reaction

F = 96500 Jmol-1

Solve for K, use 298 for temperature (assuming standard conditions), and since you have Eo, solve for E.

[Answer: see above]