Solubility help please urgent!

Question

Vinegar is a solution of ethanoic (acetic) acid (CH3COOH) in water. If 100 mL of vinegar contains 4.0 g of ethanoic acid, how do i find the molar concentration of ethanoic acid in vinegar?

Answer 1

molecular weight of CH3COOH =  60 g/mol

So 4 g of ethanoic acid = 4 /60 = 0.066 moles

Molar conc = 0.066 / 100 mol/ml =6.6 * 10^-4 mol /ml = 0.66 mol/L

Answer 2

I could tell you but that wouldn't help you. Stoichiometry was not my most favourite subject in the sciences.