Question:

Solve 14(p^2-1)=45p?

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14(p^2-1)=45p

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  1. algebraically manipulate the starting expression into a quadratic formula.  this will be p^2 - 3.21p - 1 = 0.  use the quadratic formula and you will get P = -.286 or 3.496


  2. 14p - 45p - 14 = 0

    (7p +2)(2p - 7) = 0

    p = -2/7 or 7/2

  3. 14(p^2 - 1) = 45p

    14p^2 - 45p - 14= 0

    (7p + 2)(2p - 7)=0

    Hence, p = -2/7 or 7/2 (ans)

  4. p = -2/7 or 7/2

  5. 14(p^2-1)=45p

    14 (2p-1)=45p

    28p-14=45p

    14p=45p

    p=p PEEEEEEEEEEEE
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