Question:

Solve 4x2 + x - 14 by factoring?

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Solve 4x2 + x - 14 by factoring?

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  1. (4x + 2)(x - 7)

    therefore,

    4x + 2 = 0

    4x = -2

    x = -1/2

    and

    x - 7 = 0

    x = 7


  2. 4x^2 + 8x - 7x - 14

    = 4x(x+2) -7(x+2)

    = (4x-7)(x+2)

  3. (4x-7)(x+2)

  4. I would be happy to explain and provide online resources for factoring, but need some more information.

    Is your question:

    "Four (times) x (times) two (plus) x (minus) 14" ?

    Or, is your equation "Four (times) x (squared)" ?

  5. alright to solve this the first step is to take the coefficient of the leading term (4x^2) and multiply it by the last tern (-14) this gives you -56

    next step is to find 2 numbers that when multiplied = -56 and when you add them they = the coefficient of the middle term

    so in this example your numbers are 8 and -7 because 8*-7 equals -56 and 8+-7 equals 1

    then you rewrite the trinomial with those numbers with the variable of the middle term like so...

    4x^2 + 8x - 7x - 14

    next you factor by grouping:

    you can take 4x out of the first set of terms giving you

    4x(x+2) - 7x - 14

    you can take -7 out of the second set of terms giving you

    4x(x+2) - 7(x+2)

    at this point you have your factors...what is common to both terms is a factor (x+2) and what is left is a factor (4x-7) is a factor so....

    the solution is (x+2)(4x-7)

    to check if it is correct you just FOIL the 2 binomials, if it results in the original trinomial your answer is correct

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