Question:

Solve 4y'' - 4y' + y = 0?

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solve this second order differential equation such that y(0)=0 and y(1)=1

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  1. 4y"-4y'+y=??????????????????????????????...




  2. 4y'' - 4y' + y = 0

    Find the characteristic equation:

    4r^2 - 4r + 1 = 0

    4r^2 - 2r - 2r + 1 = 0

    2r(2r - 1) - (2r - 1) = 0

    (2r - 1)(2r - 1) = 0, r = 1/2, r = 1/2

    y = Ae^(t/2) + Bte^(t/2)

    where A and B are the coefficients to be determined from the initial values.  


  3. 40-40+0=0 i guess thats right i am not good with math.

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