Question:

Solve This Math Problem!!?

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Five pumpkins are weighed two at a time in all ten sets of two. The weights are recorded as 16, 18,19, 20, 21, 22, 23, 24, 26, and 27 pounds. All individual weights are also integers. How much does each pumpkin weigh?

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  1. weight of all 5

    = (16+18+19+20+21+22+23+24+26+27) / 4

    = 216 / 4

    = 54

    weight of middle pumpkin

    = 54 - 16 - 27

    = 11 lbs

    lightest pumpkin

    = 18 - 11

    = 7 lbs

    second lightest pumpkin

    = 16 - 7

    = 9 lbs

    heaviest pumpkin

    = 26 - 11

    = 15 lbs

    second heaviest pumpkin

    = 27 - 15

    = 12 lbs

    answer = 7, 9, 11, 12 and 15 pounds.


  2. The five pumkins weighs individually 14,6,10,12, and 12 pounds.If anybody interest a can derive the way of answer.

    contact me kailai1944@yahoo.com

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