Solve. X^3 + 9x^2 + 20x = 0?

Question

I don't know what do do because the equation isn't in the form of x^4 9x^2

Please help me!!

Answer 1

first factor out an X

x(X^2+9x+20)=0

x(X+5)(X+4)=0

X=0

X=-5

X=-4

Answer 2

x (x + 4) (x +5)

x=0

x = -4

x=-5

Answer 3

Take out the common factor of x

x(x2 + 9x + 20) = 0

Factor the rest of the equation

x (x+4) (x+5) = 0

Solve for x

x = 0

x+ 4 = 0

x = -4

x+ 5 = 0

x = -5

Answer 4

x(x^2 + 9x + 20) = 0

x(x+5)(x+4)

So x = 0, -4, -5