Solve algebraically. 3/4=1-(3x-2/x+1)?

Question

The problem reads: 3 "over" 4 = 1 - (3x-2) "over" (x+1).

Answer 1

Group numbers and variables (x) on opposite sides:

3/4 - 1 = -(3x-2)/(x+1)

Simplify the left side:

-1/4 = -(3x-2)/(x+1)

Multiply both sides by -1 (in other words, change the sign of both sides)

1/4 = (3x-2)/(x+1)

Multiply both sides by the denominator of the right side, to eliminate fractions.  The x+1 on the right will then cancel out.

1/4*(x+1) = (3x-2)

Multiply both sides by 4 to eliminate the 1/4:

(x+1) = 4(3x-2)

Simplify:

x+1 = 12x-8

Again, group numbers and variables on opposite sides:

(add 8 to both sides and subtract x from both sides)

x+1+8-x = 12x-8+8-x

Simplify:

9 = 11x

Divide by 11:

9/11 = x

There's your answer.

Of course, that's the very step-by-step way.  You can combine many of those steps together, but I spelled it out for clarity.

Good luck!

Answer 2

3/4 = ( x + 1 - 3x + 2) / ( x + 1 )

3/4 = ( 3 - 2x ) / ( x + 1 )

3x + 3 = 12 - 8x

11x = 9

x = 9/11