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Solve by factoring: p(p-3)^2 -4(p-3)^3 =0?

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Solve by factoring: p(p-3)^2 -4(p-3)^3 =0?

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  1. I get:

    P(P-3)^2 - 4(P-3)^3 = 0

    (P-3)^2 [P-4(P-3)] = 0

    (P-3)^2 (-3+12) = 0

    P = 3, P = 4


  2. p(p-3)^2 -4(p-3)^3 =0

    (p-4)(p-3)^2=0

    So p-4 = 0 -----> p =4

    (p-3)^2 = 0 -----> p =3


  3. p(p-3)^2 -4(p-3)^3 =0

    (p - 3)^2[p - 4(p - 3) = 0

    (p - 3)(p - 3)(p - 4p + 12) = 0

    (p - 3)(p - 3)(-3p + 12) = 0

    p = 3, 3, 4
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