Solve by factoring y^6+27 and 3x+81x^4 Can anyone solve this?

Question

Solve by factoring y^6+27 and 3x+81x^4 Can anyone solve this?

Answer 1

They're both of the type called a sum of cubes:

x^3 + y^3 = (x + y)(x^2 - xy + y^2)

y^6 + 27 = (y^2)^3 + 3^3

3x + 81x^4 = 3x(1 + 27x^3) = 3x(1 + (3x)^3)

You should be able to work them from there.  Learn the patterns!