Question:

Solve by substitution method

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2x 5y=32

x=68-9y

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  1. I'm assuming that the two equations are:

    2x + 5y = 32

    x = 68 - 9y

    Substitute the expression '68 - 9y' from the second equation in place of 'x' in the first equation:

    2(68 - 9y) + 5y = 32

    Multiply it out:

    136 - 18y + 5y = 32

    Combine terms and subtract 136 from both sides:

    -13y = 32 - 136

    -13y = -104

    Divide by -13:

    y = 8

    Plug the value 8 into equation 2 in place of 'y':

    x = 68 - (9 * 8)

    x = 68 - 72

    x = -4

    The solution is x = -4 and y = 8.


  2. 2x+5y=32

    x=68-9y

    substitute x into 2x+5y=32

    2(68-9y)+5y=32

    136-18y+5y=32

    136 -13y=32

    -136       -136

    -13y=-104

    y = 8

  3. Hi,

    is it a correct equation ?

    do you mean 2x + 5y = 32 ?

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