Solve each system of equations using any method.?

Question

x-2y=4

2x+2y=8

Answer 1

you do this by substitution

you take the first equation and leave x alone on one side

x=4+2y

and put this in the place of x in the other equation

2(4+2y)+2y=8

8+4y+2y=8

6y=0

y=0/6=0

and thus x=4+2(0)

x=4

hope this has helped:):)

Answer 2

x-2y=4

2x+2y=8

x=4+2y

2(4+2y)+2y=8

8+4y+2y=8

8+6y=8

6y=0

y=0

x=4

Answer 3

x-2y=4

2x+2y=8

--------------

    x-2y=4

-  2x+2y=8

-----------------

-x= -4

x=4

by substitution

x-2y=4

4-2y=4

2y=4-4

2y=0

y=0

Answer 4

1) x-2y=4

x = 2y + 4

2) 2x+2y=8

2(2y + 4) + 2y = 8 {substitute for x from equation 1}

4y + 8 + 2y = 8

6y = 0

1) x = 2(0) + 4

x = 4

check

2) 2(4) + 2(0) = 4

4 = 4

Answer 5

x =4, y=0

x= 4+2y

2(4+2y) +2Y = 8

y=0

x-2(0)=4

x=4

Answer 6

x - 2y = 4, 2x + 2y = 8

I'll solve through the Addition method:

(x - 2y = 4) + (2x + 2y = 8) = (3x = 12)

3x = 12

x = 4

x - 2y = 4

4 - 2y = 4

-2y = 0

y = 0

ANSWER: x = 4, y = 0; point (4, 0) when graphed