Solve equation over the set of complex numbers √4 - 2y + 7 = 3?

Question

I must have an answer from a b or c.

Answer 1

2y=4+2=6

==>y=3

Answer 2

1st interpretation:

√(4 - 2y + 7) = 3

4 - 2y + 7 = 9

2y = 2

y = 1

2nd interpretation:

√4 - 2y + 7 = 3

2y = 2 + 7 - 3

2y = 6

y = 3

Answer: it's either 1 or 3

Answer 3

sqrt(4) - 2y + 7 = 3

2 - 2y + 7 = 3

9 - 2y = 3

-2y = -6

y = 3

Are you sure the equation is correct, are there parenthesis missing or something?

With the additional information:

sqrt(4 - 2y + 7) = 3

sqrt(11 - 2y) = 3

11 - 2y = 9

-2y = -2

y = 1

None of the choices are correct, if you try plugging each of them in, you do not get a correct answer.  The closest one is zero though.

sqrt(4 - 2(-6) + 7) = 3

sqrt(4 + 12 + 7) = 3

sqrt(23) = 3

4.7958315233127195415974380641627 != 3

sqrt(4 - 2(-10) + 7) = 3

sqrt(4 + 20 + 7) = 3

sqrt(31) = 3

5.5677643628300219221194712989185 != 3

sqrt(4 - 2(0) + 7) = 3

sqrt(4 - 0 + 7) = 3

sqrt(11) = 3

3.3166247903553998491149327366707 != 3

Answer 4

√(4 - 2y + 7) = 3

√(11 - 2y) = 3

(11 - 2y) = 3^2

11 - 2y = 9

-2y = 9 - 11

-2y = -2

2y = 2

y = 2/2

y = 1

Answer 5

If the root is only on 4 then

2 - 2y + 7 = 3

6 = 2y

y = 3

awesome not an answer

how far does the sqroot go

Answer 6

I  actually worked it backwards by putting in answers a-b-c in place of y.

Your answer is 0

4-2(0) +7 = 3

4-0+7=3

4+7=3

11=3

square root of ll is 3.3

Now how to slove it correctly I am still working on

When U work it out the correct way I still get 1......