Solve for X and Y using a system of equation? (warning: exponents are involved)?

Question

4^x(8^y) = 2

3^3x(9^2y) = 27^(2/3) or 9

Answer 1

4^x = 2^(2x)

8^y = 2^(3y)

2^(2x) * 2^(3y) = 2

2^(2x+3y) = 2^1

2x+3y = 1

3^(3x)* 3^(2*2y) = 3²

3^(3x+4y) = 3²

3x+4y = 2

So your system of equations is

2x+3y = 1

3x+4y = 2

Answer 2

write 4^x as 2^2x ,8^y as2^3y

2^(2x+3y)=2

2x+3y=1

similarly 3^(3x+4y)=3^2

3x+4y=2

solving x=2 y=-1