Solve for c: p + n = c + (2/c)?

Question

Solve for c: p + n = c + (2/c)?

Answer 1

(p+n)c = c^2 + 2

c^2 - (p+n)c + 2 = 0

c = [(p+n) +/- sqrt((p+n)^2-8)]/2

Answer 2

First, let a = p + n

This makes it easier to handle...and it gives you: a = c + 2/c

Then go to it....ca = c² + 2

==> c² - ca + 2 = 0

You get c = ½(a - √(a² - 8))

Then put back in for what "a" is and you're done.

Answer 3

well, antone could know that you fool..

only clever people know that c:p+n=c+(2/c)

is poo...so tata!

Answer 4

Multiplying both sides by "c"

c(p + n) = c^2 + 2

Rearranging the above,

c^2 - (p+ n)c + 2 = 0

Applying the quadratic formula to the above ,  

a = 1

b = -(p + n)

c = 2

the roots are as follows

c = {(p + n) + sqrt [(p + n)^2 - 8]}/2

and

c = {(p + n) + sqrt [(p + n)^2 - 8]}/2