Question:

Solve for t using natural logarithms. 6e^9t=8e^8t?

by Guest59238  |  earlier

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if you can tell me exactly how to put it in the calculator, that would really help.

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  1. First, divide both sides by 2:

    3e^(9t)=4e^(8t)

    Take the ln of both sides:

    ln[3e^(9t)]=ln[4e^(8t)]

    Using rules of logarithms:

    ln(3)+ln[e^(9t)]=ln4 + ln[e^(8t)]

    Using definition of natural logarithms, this simplifies to

    ln(3) +9t = ln(4) +8t

    Subtract 8t from both sides:

    ln(3)+t=ln(4)

    Subtract ln(3) from both sides:

    t=ln(4)-ln(3)

    Use rules of logarithms:

    t=ln(4/3)

    Press 4

    Press / ("divided by")

    Press 3

    Press =

    press ln

    You should get about .2877

    _/


  2. 6e^9t-8e^8t=0

    e^8t(6e^t-8)=0

    e^8t=0 (not possible) or e^t=4/3

    =>t=log[e](4/3)

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