Solve for the indicated variable in the following expressions:?

Question

27) u(v+2) + w(v-3) = z(v-1)

solve for v

29) [ (a-cx)/(b+dx) ]+ a = 0

solve for x

the answer to 27 is v=(3w-2u-z)/(u+w-z)

the answer to 29 is x= -a(b+1) / (ad-c)

the problem is i cant get to the answer show me how????

i think ive done these problems about 20 times :(

Answer 1

Problem #27

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Given:

u(v+2) + w(v-3) = z(v-1)

Multiply terms:

vu + 2u + wv - 3w = zv - z

Move "v" terms to one side, non-"v" terms to the other:

vu + wv - zv = - z - 2u + 3w

Factor the left side:

v(u + w - z) = - z - 2u + 3w

Divide both sides by (u+w-z);

v = ( -z - 2u + 3w )/(u+w-z)

Re-order to fit the given answer:

v = ( 3w -2u -z )/(u+w-z)

Problem #29

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Given:

[(a-cx)/(b+dx)]+ a = 0

Move "a" to right side:

(a-cx)/(b+dx) = -a

Multiply both sides by (b+dx):

(a-cx) = -a(b+dx)

Distribute the "-a" on the right side:

a-cx = -ab - adx

Move "x" terms to one side and non-"x" terms to the other:

adx - cx = -ab -a

Factor:

x(ad - c) = -a(b+1)

Divide both sides by "ad-c":

x = -a(b+1)/(ad-c)