Solve for x, (2x)/(4Ï€) + (1-x)/2 =0?

Question

Please show all work and solve for x asap

First answer gets 10 points and five stars

Answer 1

The least common denominator is 4 pi.

So we have to take the (1 - x) / 2 term and multiply both numerator and denominator by 2 pi.

That fraction becomes [(1 - x) * 2 pi] / 4 pi      (* for multiplication.)

Now the equation looks like:

2x + 2 pi - (2x * pi)

----------------------------   = 0

4 pi

Multiply both sides of the equation by 4 pi, getting

2x + 2 pi - (2x * pi) = 0

Divide both sides of the equation by 2

x + pi - (x * pi) = 0     Group and factor the x terms to the left.

x * (1 - pi) + pi = 0

Subtract pi from both sides.

x * (1 - pi) = - pi

Divide both sides of the equation by (1 - pi)

x = (- pi ) / (1 - pi)    <<<<<  Answer

Answer 2

2x/4pi + (1-x)/2 = 0

simplifying,

x/2pi + (1-x)/2 = 0

combining the two terms (LCD),

(x + pi -xpi)/2pi = 0

cross multiply

x + pi - xpi = 0

since pi is a constant, transpose it to the other side of the equation

x-xpi = -pi

isolate x (factoring)

x(1-pi) = -pi

divide both sides by (1-pi)

x = -pi/(1-pi)  

Answer 3

(2x)/(4π) + (1-x)/2 =0 becomes (2x)/(4π) =- (1-x)/2

Cross multiply to get:

(2x)(2) =- (1-x)(4π)

4x=4π - 4πx

put x's together to get:

4x-4πx = 4π

Cancel 4 since every term has a 4 to get

x-πx=π

Reverse distribute x to get

x(1-π)= π

and x=π/(1-π)

done

Answer 4

2x/4pi + (1-x)/2 = 0

2x + 2pi - 2x(pi) = 0

x + (pi) -x(pi) = 0

x(1 - pi) = -pi

x = -pi/1-pi

x = -3.1416/2.1416

x = 1.467

Answer 5

(2x)/(4π) + (1-x)/2 =0

4x/4π + 1-x = 0

4x +4π -4πx = 0

(4-4π)x = -4π

x = -4π / (4 - 4π)

x = -4π / 4(1-π)

x = -π / (1-π)

Answer 6

value of pi =3.14,app. take it as 3

         2x/4*3+(1-x)/2 =0

         2x/12+(1-x)/2 =0

you have got different denominators,so take l.c.m

            lcm =12

so,you will multiply 2nd term numerator and denominator by 6

              2x/12+6(1-x)/12 =0

              2x+6-6x=0

              -4x= -6

               so,x = 3/2