Question:

Solve for x, x-sinex=0... where x is not equal to zero?

by  |  earlier

0 LIKES UnLike

thanks in advance..

 Tags:

   Report

1 ANSWERS


  1. Subtract x from each side,

    x = sin x

    For trig, x is in natural units (radians). Since -1≤ sin x ≤ 1, only values for x between -1 and 1 need be checked.

    Sin is determined numerically. Exploring it in Excel, there are no values that meet the requirements except x=0.

    Now, d/dx sin x = cos x.

    This means that sin x at zero starts out changing at the same rate as x at x=0 (since cos 0 = 1). But it falls off as x gets away from zero, and the greater is gets, the more it falls off. Performance for x<0 is the same. Thus, no roots other than zero.

Question Stats

Latest activity: earlier.
This question has 1 answers.

BECOME A GUIDE

Share your knowledge and help people by answering questions.
Unanswered Questions