Solve for x. 3x^2= -16x -16?

Question

Solve for x please . Provide an integer or a simplified fraction for this quadratic equation.

Thanks

Answer 1

x = -4/3 or -4

Answer 2

You need to have the equation in standard form...

3x^2 + 16x + 16 = 0

Now factor

(3x + 4)(x + 4) = 0

So, by the zero property

3x + 4 = 0 or x + 4 = 0

so

x = -4/3 or x = -4

Answer 3

3x^2 = -16x - 16

3x^2 + 16x + 16 = 0

3x^2 + 12x + 4x + 16 = 0

(3x^2 + 12x) + (4x + 16) = 0

3x(x + 4) + 4(x + 4) = 0

(x + 4)(3x + 4) = 0

x + 4 = 0

x = -4

3x + 4 = 0

3x = -4

x = -4/3

∴ x = -4 , -4/3

Answer 4

3x^2= -16x-16

3x^2+16x+16= 0

( 3x+  4 )( x+    4 ) = 0

3x+4= 0

x= -4/3

x+4= 0

x= -4

Answer 5

3x^2+16x+16=0

(3x+4)(x+4)= 0

x = -4/3 or -4

Answer 6

Simplifying: 3x2 = -16x + -16

Reorder the terms: 3x2 = -16 + -16x

Solving for variable 'x'.

Reorder the terms: 16 + 16x + 3x2 = -16 + -16x + 16 + 16x

16 + 16x + 3x2 = 0

(4 + x)(4 + 3x) = 0

4 + x = 0.

4 + -4 + x = 0 + -4

x = 0 + -4

x = -4

4 + 3x = 0

4 + -4 + 3x = 0 + -4

3x = 0 + -4

3x = -4

Divide each side by '3'.

x = -1.333333333

Simplifying

x = -1.333333333

Solutionx = {-4, -1.333333333}