Solve for x?????????

Question

14) Solve for “x”.

( x - 4)^2 - 25 = 0

[[ btw thats ( x - 4 ) ^2 ...the ^2 means Squared ]]

is it...

a.) x = 1, x = 9

b.) x = –1. x = 9

c.) x = 9, x = –9

d.) x = 1, x = –1

15) Solve for “y”.

81(y - 9)^2 - 81 = 0

[[btw ^2 = squared]]

Answer 1

(x-4)^2=5^2

which implies x-4 = 5 ie x=9

also

-5^ 2 is also 25 so we need to equate d equation x-4=-5

which gives d ans x=-1 so d ans is b.

as for the nxt ques take 81 common n since 0/81=0

v gt (y-9)^2 -1^2 = 0

y-9=1

therefore d answ is y=10 n equate it wid -1 d ans is y=8

Answer 2

14.)

(x-4)^2-25=0

          +25 +25

(x-4)^2=25

take the square root of both sides

x-4=+-5

  +4  +4

x= -1, 9

b.) x = –1. x = 9

15.) add 81 to both sides, then divide both sides by 81, then you get

(y-9)^2=1

find the square root of both sides

y-9=(plus or minus)(+-)1

add 9 to both sides and you get

y= 8 y= 10

Answer 3

14. b

15. y= 8 or 10

Answer 4

14)

(x - 4)^2 = 25

SQRT((x-4)^2) = +/-5

x - 4 = +/-5

x = +/-5 + 4

Therefore,

x = -1 or 9 or

x is the element of the set {-1, 9}

The answer is b.

15) 81 (y-9)^2 - 81 = 0

81(y-9)^2 = 81

(y-9)^2 = 81/81

(y-9)^2 = 1

y - 9 = +/-1

y = +/-1 + 9

So, y = 10 or 8

or y is the element of the set {8, 10}

Answer 5

14. b.

15. 18 or 0.

y - 9 = 9  or y - 9 = -9

y      =18  or  y    = 0