Solve sqrt(3x+10) = x+2?

Question

1)sqrt(3x+10) = x+2

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Answer 1

sqrt(3x+10)=x+2

Square both sides:

3x+10 = sqr(x+2)

=&gt;    3x+10 = sqr(x) + 4x + 4

rearrange to get

        sqr(x) + x - 6 = 0

=&gt;    (x+3)(x-2)=0

=&gt;    x+3 = 0 or x-2 = 0

=&gt;    x = -3 or 2

       ========

Answer 2

first , square both sides

( SQRT 3X + 10 ) ^2 = ( X + 2 ) ^2 =            3x+10 = X^2 +4X + 4

combine terms  X^2 + X -6 =0   factor  (X+3)(X-2 )  so X = -3, 2

Proof  SQRT  ( 3x2 ) + 10 = 2 + 2    4 = 4  

Answer 3

3x + 10 = (x + 2)²

3x + 10 = x² + 4x + 4

x² + x - 6 = 0

(x + 3)(x - 2) = 0

x = - 3 , x = 2

Answer 4

sqrt (3x + 10) = x + 2

3x + 10 = (x + 2)^2

3x + 10 = x^2 + 4x + 4

x^2 + 4x - 3x + 4 - 10 = 0

x^2 + x - 6 = 0

(x + 3)(x - 2) = 0

x = -3 ...OR... x = 2

Answer 5

square both  sides  to eliminate  sqrt

3x+10= ( x+2)^2

3x+10= x^2+4x+4

-x^2-4x+3x+10-4= 0

-x^2-x+6= 0

x^2+x-6=0

( x-2) ( x+3) = 0

x-2=0

x= 2

x+3= 0

x= -3

Answer 6

1)Square both sides of the equation.

3x+10=(x+2)(x+2)

3x+10=x^2+4x+4

Move everything to one side of the equation.

x^2+x-6=0

Factor.

(x+3)(x-2)=0

Solve

x+3=0

x=-3

x-2=0

x=2

Check.

√(16)=2+2

4=4

√(1)=/=-1

Therefore, the solution is 2.

Answer 7

=&gt;3x+10=(x+2)^2

=&gt;3x+10=x^2+4x+4

=&gt;x^2+x-6=0

=&gt;x^2+3x-2x-6=0

=&gt;(x+3)*(x-2)=0

=&gt;x+3=0  or  x-2=0

=&gt;x=-3 or 2

but x cant be -3 as on substitution we obtain sqrt(3x+10) will be -1 but sqrt cant be a negetive hence x=2

Answer 8

3x+10=x^2+4x+4

  x^2+x-6=0

  (x+3)(x-2)=0

   x=2