Question:

Solve the equation... l5x - 8l = lx + 4l?

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solve the equation... l5x - 8l = lx + 4l

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  1. Let's find x in 3 steps:

    1)x>1.6 then  5x - 8 = x + 4 => x=3 (it is in the range)

    2)  -4<x<1.6 then  -5x + 8= x+4  => x= 2/3=0.(6) ( also in the range)

    3)  x< - 4 then - 5x + 8 =-x- 4  => x=3 ( it is out of the range!!!)

    Answers: x1 = 3  x2=2/3


  2. 5x-8= x+4

    5x=x+12

    4x=12

    x=3

    5x-8= -x-4

    5x= -x+4

    6x=4

    x=2/3


  3. 5x-8= x+4

    4x=12

    x=3

    @

    5x-8= -x-4

    6x=4

    x=2/3

    so x=3,2/3

  4. There is two way to answer the question: but there is 1 answer in it

    since its an absolute question there is two sides to the question positive and negative.

    1.(5x - 8) = (x + 4) subtract the left side by x and add an 8 to the right to keep the x's in one place and the numbers in one place,you can do vise versa in terms of sides.

    2. u should get 4x = 12, divide each side by 4 to the answer for x which is x = 3.

    other way we you should do cuz sometimes the answer is not always the same

    1. -(5x - 8) = -(x + 4) which should end up being -5x + 8 = -x - 4

    2. do the same cancellations and yo get -4x = -12, divide each side  by -4 and you still get x = 3

    your done.


  5. I'm sorry, I don't get the I's. Are we solving for x?

  6. I5x-8I = Ix + 4I  

    5x - 8 = x + 4    or    -5x + 8 = x + 4

    4x - 8 = 4          or     -6x + 8 = 4

    4x = 12             or     -6x = -4

    x= 3                 or      x = 4/6 ... which reduces to 2/3

    So x = 3 or x = 2/3

  7. Hi,

    l5x - 8l = lx + 4l breaks into 2 equations to solve without absolute value bars:

    5x - 8 = x + 4 or 5x - 8 = -x - 4

    4x = 12

    x = 3 <==ANSWER

    5x - 8 = -x - 4

    6x = 4

    x = 2/3 <==ANSWER

    Both answers are good.

    I hope that helps!! :-)

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