Solve the equation.x^3/4 - 16 = 0?

Question

Solve the equation.x^3/4 - 16 = 0?

Answer 1

x=4

4^3/4-16=0

64/4-16=0

16-16=0

0=0

Answer 2

0

Answer 3

x^3/4 - 16 = 0

=> x^3/4 = 16

=> x = (16)^4/3

=> x = (+/- 2)^(4 x 4/3)

=> x = (+/- 2)^16/3 ==ANSWER

Answer 4

add 16 to both sides then its going to be

X^3/4=16 then punch it in to your calculator...  

Answer 5

x^3 /4 = 16 (transposition)

x^3 = 16 *4 (cross multiplication)

      = 4 *4*4 = 4^3

so x = 4

Answer 6

You want to isolate the x's. Since there is only one x in this case it's easy in the sense that you don't have to use a cubic equation formula or solving software. So add 16 to both sides:

x^3/4 = 16

Then multiply both sides by 4

x^3 = 64

Then take the cube root on both sides

x = 4

(Note: it can't be -4, because -4^3 = -64)

Answer 7

I SUSPECT that you mean :-

x³ / 4 - 16 = 0 and NOT as written.

x³ / 4 = 16

x³ = 64

x = 4

Answer 8

If the equation is x^(3/4) - 16 = 0:

x^(3/4) - 16 = 0

x^(3/4) = 16

[x^(3/4)]^(4/3) = 16^(4/3)

x = 16^(4/3)

x = [16^4]^(1/3)

x = 65536^(1/3)

x equals the third root of 65536, or about 40.3175.

If the equation is [x^3]/4 - 16 = 0:

[x^3]/4 = 16

x^3 = 64

x = 64^(1/3)

x = 4

Answer 9

FIRST OFF, ADD 16 to both sides.

You get x^(3/4) = 16

You want the x to be x only, without any exponents. So to get rid of it:

STILL EDITING--