Solve the equation x^4-5x^3-3x^2+13x+10?

Question

oh sorry it equals 0

Answer 1

x=-1 or x=2 or x=5

Normally there are 4 roots but here we have

two times x=-1 as root (multiplicity 2)

Answer 2

x^4-5x^3-3x^2+13x+10=0

-1,2,5 are zeros by trial and error.

x=-1

x=2

x=5

Answer 3

This is only an expression not an equation..

Answer 4

f ( x ) = x^4 - 5x³ - 3x² + 13x + 10

f ( 2 ) = 16 - 40 - 12+ 26 + 10

f ( 2 ) = 52 - 52

f ( 2 ) = 0

Thus x - 2 is a factor of f (x)

To find other factors , use synthetic division :-

2 |1____-5____-3____13____10

_ |_____ 2____-6___-18____-10

_ |1____-3____-9____-5____ 0

(x - 2) (x³ - 3x² - 9x - 5) = 0

Consider x³ - 3x² - 9x - 5

(- 1 )³ - 3 + 9 - 5 = - 9 + 9 = 0

Thus x + 1 = x - (-1) is a factor

- 1 |1_____-3_____-9_____-5

__ |______-1_____ 4_____ 5

__ |1_____-4_____-5_____0

Now have :-

(x - 2)(x + 1)(x² - 4x - 5) = 0

(x - 2)(x + 1)(x - 5)(x + 1) = 0

(x + 1)² (x - 2) (x - 5) = 0

x = - 1 , x = 2 , x = 5

Answer 5

do ur own homework

Answer 6

Hi.

This one is not easy to solve but the answer you are looking for is:

x = -1 or x = 2  or x = 5

Hope this helped!

Answer 7

you can use synthetic division

hard to explain it on here so hopefully the website can help you out

scroll down a little to get to it...