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Solve the equation. y^2-10y+16=0?

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Solve the equation. y^2-10y+16=0?

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  1. y^2-10y+16=0

    (y-8)(y-2)=0

    y=8 or y=2


  2. y^2-10y+16 = 0

    factor it

    (y-8)(y-2) = 0

    therefore either y -8 = 0 or y-2 = 0

    answer:

    y= 8 and y = 2

  3. y^2 - 10y + 16 = 0

    Factors of +16 that add to - 10 are -2 & -8

    (x - 2)(x - 8) = 0

    x = 2, 8

  4. If you dont want to use factoring you can always use the quadratic equation. -b +or - Square root of b^2 -4(a)(c) all over 2(a)

    In this specific problem 1 = a

    -10= b

    16 = c

    Now plug it in and you will get your two answers

  5. Use the quadratic formula.  You should get 8 and 2.

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