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Solve the following equation for y: 2e^4y=5x^2+6?

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Solve the following equation for y: 2e^4y=5x^2+6?

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  1. 2e^4y = 5x^2 + 6

    => e^4y = (1/2) (5x^2 + 6)

    => 4y = ln (5x^2 + 6) - ln2

    => y = (1/4) [ln (5x^2 + 6) - ln2].

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