Solve the following systems of equations using Cramer's Rule. Please!?

Question

1.) 2x+3y=7

8x+12y=2

2.) 2x-y=3z=9

x +2z=3

3x+2y+z=10

Answer 1

Go here to learn how to use Cramer's rule:

http://www.purplemath.com/modules/cramer...

Set up a matrix for each problem.  Find the determinants, and use Cramer's rule.

Answer 2

1) setup matrix and calculate the determinants D,D1 and D2

2 3 7

8 12 2

x = D(1)/D  y =D(2)/D

D= 2*12 - 8*3 = 0

since D is equal to zero making denominator zero there is no definite solution to this equal in fact the 2 systems are parallel so there is no solution to this equation

hope this helps

Answer 3

1) Put the coefficients into a matrix.

[2   3] = [7]

[8 12] = [2]

Then, find the determinant (ad-bc).

Determinant = 24 - 24 = 0

Determinant equals zero, therefore you cannot solve this system of equations using Cramer's Rule.

Answer 4

solve your own problem!!  (only for the first one)

   linear system:              a(2) x + b(3) y = e(7)

                                     c(8) x + d(12) y = f(2)

..x=   {e  b}                              

.......{f   d}...ed-bf                          

.......------- = -------                        

.......{a  b}...ad-bc                        

.......{c  d}                                    

..y=   {a  e}

.......{c  f} .... af-ec

.......--------- = --------

.......{a  b} ...ad-bc

.......{c  d}

i tried solving this problem and got

{2*(78/0)} + {3*(-2/0)} = 7

cramer's rule cannot solve this problem