Solve the inequality; 8a+11<19?

Question

Solve the inequality; 8a+11<19?

Answer 1

hi friend

8a+11&lt;19

so 8a+11 is smaller than 19

so if you put a=1

8+11=19

so a must be less than1.

so you can take any negative value upto infinity the equation will satisifies.

so you can take the values between

[- infinity, 1)

so you can use use any negative value, positive value which is less thanone

so the limit is -infinity to 1

here you can take upto 0.99999

so limit

[-infinity, 1)

Answer 2

easy a =1

Answer 3

First of all, make the inequality an equation. Ignore the &#039;&lt;&#039; sign and replace it with an equal (=) sign.

8a + 11 = 19

Then solve it like a normal algebraic equation

In this case;

8a = 19 - 11

8a = 8

a = 1

Remember to put the &#039;&lt;&#039; back is as this is an inequality.

Therefore, a &lt; 1

Answer 4

Although you can replace the &lt; by = for temporary convenience, I suggest you don&#039;t do this, as you may at some stage have to multiply an inequality by a minus value, and this changes the direction of the inequality. That&#039;s not required here, but it&#039;s better to form good habits early on.

Here, you can add or subtract from both sides of the inequality, and it will still hold true. You can also divide by any positive (non-zero) number, and it will again still hold true. So just progress one step at a time.

8a + 11  &lt;  19

subtract 11 from both sides

8a  &lt;  8

divide both sides by 8

a  &lt; 1

And there you have it.