Solve this simultaneous equation?

Question

2x+y=8 and 3x^2+xy=1

give your answer in the form a+b(root)17, where a +b are integers

Answer 1

2x+y=8

3x+y=1/x

y=8-2x

3x+(8-2x)=1/x

x+8=1/x

x^2+8x-1=0

-8 +/- sqrt(68)/2

-8 +/- 2sqrt(17)/2

x= -4 +/- sqrt(17)

-8 +/- 2sqrt(17)+y=8

16=+/- 2sqrt(17)+y

x= -4 +/- sqrt(17) <======= ANSWER

y= 16 -/+ sqrt(17)<======= ANSWER

Answer 2

solve the first eq for y and substitute it into the second eq.