Question:

Solve using gauss-jordan elim. 2x + 2y +z =9, x +0 +z=4, and 0 +4y - 3z = 17?

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  1. Greetings,

    [2 2 1 | 9]

    [0 4 -3 | 17]

    [1 0 1 | 4]

    [1 1 1/2 | 9/2] (1/2)*R1

    [0 1 -3/4 | 17/4] (1/4)*R2

    [0 1 -1/2 | 1/2] (-1/2)*R1 + R3

    [1 1 1/2 | 9/2]

    [0 1 -3/4 | 17/4]

    [0 0 -1/4 | 15/4] R2 - R3

    [1 0 5/4 | 1/4] R1 - R2

    [0 1 0 | -7] (-3)*R3 + R2

    [0 0 1 | -15] (-4)*R3

    [1 0 0 | 19] R1 - (5/4)*R3

    [0 1 0 | -7]

    [0 0 1 | -15]

    x = 19, y = -7, z = -15

    Regards

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