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Solve : x + 1/x-4 = 0 and sin²x - 2sinx - 3 = 0 (0 ≤ x ≤ 2π)?

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Solve : x + 1/x-4 = 0 and sin²x - 2sinx - 3 = 0 (0 ≤ x ≤ 2π)?

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  1. y^2 - 2y - 3 = 0

    (y-3)(y+1) = 0

    So sin x = -1 (Or sin x =3, doesn't work)

    x = 3Pi/2

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