Solve (x-7)^2= (x+3)^2?

Question

The answer is two, can you help?

Answer 1

what year r u in?how wld i no

Answer 2

(x - 7)^2 = (x + 3)^2

x - 7 = ±√(x + 3)^2

x - 7 = ±(x + 3)

x - 7 = +(x + 3)

x - x = 7 + 3

0 = 10

x - 7 = -(x + 3)

x - 7 = -x - 3

x + x = 7 - 3

2x = 4

x = 4/2

x = 2

∴ x = 2

Answer 3

The given problem is (x - 7)^2 = (x + 3)^2. We can solve to find the two solutions by expanding the equations, i.e.

(x - 7)^2 = (x + 3)^2

x^2 - 14x + 49 = x^2 + 6x + 9

-14x + 49 = 6x + 9

-20x = -40

x = 2

The answer is two.

Answer 4

take squareroot of both sides

    x-7=x+3   = x-x=10  0=10

OR  expand

x^2-14x+49=x^2+6x+9   = x^2-x^2-14x-6x+49-9=0

0-20x+40 =0   -20x=-40  x=-40/-20  x=2  okay no wonder

Answer 5

(x-7)^2= (x+3)^2

x^2+49-14x = x^2+9+6x  //  (a+b)^2 = a^2+b^2+2ab

x^2+40 = x^2+20x

20x = 40

x=2

Hence proved.

Give 10 points for me...