Solving Equations With Exponents?

Question

How do you solve something like..

2x^2 - 5x = 7

Answer 1

2X^2 - 5X= 7

2X^2 - 5 X - 7 = 0

2X^2 +2x -7x - 7 = 0

2x( X+1) -7(X+1)

2x-7)(x+1) ans

The basic principle is to make   sure the  the common factors can be found out  from coefficient of X.

In our case it it was -5x  which we wrote as +2x-7x so that we can get common factors

Answer 2

2x^2 - 5x - 7=0

(2x - 7) (x + 1) = 0

2x - 7 = 0      x + 1 = 0

2x = 7           x = -1

x = 7/2

Answer 3

This is a quadratic equation.  You solve by setting the equation equal to zero, or

2x^2 - 5x - 7 = 0

Then, you can solve by factoring, or by using the quadratic formula.

This equation will factor---

(2x - 7)(x + 1) = 0

2x - 7 = 0, so x = 7/2

x + 1 = 0, so x = -1

Check both answers in the original equation.

Answer 4

u move the 7 to the other side and then factor

2x^2 - 5x = 7

2x^2 - 5x -7= 0

(2x-7)(x+1)=0  set each paren = 0 and solve

x= 7/2 or -1