Solving Quadratic equations by factoring?

Question

Okay so i need help!

(I'm going to type the exponents like ^2 <- that would be to the second power)

i understand how to pretty much do it but in a problem like this:

6x^2 - 27x +27= 0

how do i check and see if my answers are right?

and my answers were x= 3/2 and x=3

Answer 1

To check to see if the answers are correct, substitute them into the original quadratic equation, and if they yield an output of 0, which is 0 = 0 for the solved equation, then bingo, you did it right.

J.C

Answer 2

This has already been asked and answered, by you.

To check your answers, simply plug them into the original equation and see if they work.

Answer 3

6x^2 - 27x +27= 0

ok by facotring

pull out a factor 3

3(2x^2 -9x+9)=0

3(2x  -3)(x-3   ) =0

by the zero property each bracket equals zero.

either 3=0 or 2x-3=0 x-3=0

so 2x=+3 or x = +3

x = 3/2 x = +3

Answer 4

This would be kind of a hard equasion to factor since you aren&#039;t dealing with whole numbers.

To solve it you must use the quadratic formula.

Once you get your answers you can plug both of them back into the original equasion and if your answer equals 0 you are correct.

6(1.5^2) - 27(1.5) + 27 = 0

6(2.25) - 40.5 + 27 = 0

13.5 - 40.5 + 27 = 0

-27 + 27 = 0

0 = 0

Since the ending result is 0, 3/2 is a correct answer

6(3^2) - 27(3) + 27 = 0

6(9) - 81 + 27 = 0

54 - 81 + 27 = 0

-27 + 27 = 0

0 = 0

Since the ending result is 0, 3 is also a correct answer