Solving a linear equation problem solving?

Question

At a vegetable stand, you bought 3 pounds of peppers for $4.50. Green peppers cost $1 per pound and orange peppers cost $4 per pound. Find how many pounds of each kind of pepper you bought.

Answer 1

Okay, so you need to use Simultaneous equations to solve this.

We can establish two equations from the question, letting x be number of Green peppers and y be number of Orange peppers.

x + y = 3 (This is because the number of each amount adds up to 3)

x + 3y = 4.5 (Green costs $1 per pound, Orange costs $3)

Therefore, we can re-arrange the first equation to be:

x = 3 - y. (Subtract y from both sides)

We can then substitute x into the second equation to make it all terms of y.

3 - y + 3y = 4.5 (x = 3 - y)

Which then becomes...

3 - 2y = 4.5

And then...

2y = 1.5

Finally...

y = 0.75.

So, we know how many orange peppers we bought. We can then substitute this into the first equation to get how many Green peppers.

x + 0.75 = 3

Which can be made to...

x = 2.25

So your final answer should be:

I bought 2.25 pounds of Green peppers, and 0.75 pounds of Orange peppers.

Answer 2

x + y=3

x + 4y= 4.5

x=3-y

3-y + 4y=4.5

3y=1.5

y=.5

x=2.5

Checking

2.5+4(.50)=4.5

You bought 2.5 lbs of green and .5 lbs of orange.

Answer 3

lets assume  X lbs of Green Pepeprs  and Y lbs of orange  one purchased.

you can now form  two equations   that is

X+Y =  3 based on weight

X+4Y = 4.50 based on cost

solving two

you get Y = 0.5 lbs  and X = 2.5 lbs ans.