Solving equations using the graphing method?

Question

i know you have to get it into the y=mx+b form

but how do i do that with this equation?

12=(x+3)^2-2

Answer 1

(x+3)^2 = 12+2

x+3 = sqroot 14

x= sqroot 14    -3

x= +3.741657387 - 3 = 0.741657387

and x= -3.741657387 -3 = -6.741657387

since no y term, y=0

you have 2 points on the graph  (-6.7,0) and (0.7,0 )

Answer 2

y = mx + b represents a linear graph (ie a straight line).

The equation you have listed is actually a quadratic equation of the form y = mx^2 + bx + c

12 = (x+3)^2 - 2

12 = (x+3).(x+3) - 2

0 = x^2 + 6x - 5

Answer 3

Firstly have you written the question correctly???

y=mx+b is linear and you have a quadratic in x...

Given this

12=(x+3)^2-2

14=(x+3)^2

so x=-3±sqrt(14)

So I come back to my question above...