Question:

Solving for different letters, a, b?

by  |  earlier

0 LIKES UnLike

solving for 'a'?

BA + C = D

1. A = D - B - C

2. A = (D - C)/B

3. A = (C - D)/B

NOW, SOLVING FOR B

A = 3(B + C)

1. B = (A - C)/3

2. B = (3A - C)/3

3. B = (A - 3C)/3

 Tags:

   Report

3 ANSWERS


  1. 1st problem:

    BA + C = D

    BA = D - C

    A = (D - C)/B

    Answer: 2. (D - C)/B

    2nd problem:

    A = 3(B + C)

    B + C = 1/3A

    B = 1/3A - C

    B = (A - 3C)/3

    Answer: 3. B = (A - 3C)/3


  2. the first one is 2. A = (D - C)/B

    the next one is 3. B = (A - 3C)/3


  3. BA + C = D

    BA = D - C

    A = (D - C) / B

    ANSWER: 2

    A = 3(B + C)

    A = 3B + C

    3B = A - C

    B = (A - C) / 3

    ANSWER: 1

Question Stats

Latest activity: earlier.
This question has 3 answers.

BECOME A GUIDE

Share your knowledge and help people by answering questions.
Unanswered Questions