Solving for x square root?

Question

(x^2-24/28=0 x^2=24/28..here you can simply right? so..+-sqrt (6/7)

another questiion (24/26)^3/4 so.. root4(24/26)^3... then do root4 of 24 than root 4of 26 rite or you can simplify the 24/26 than do the root?

Answer 1

x^2 - (24/28) = 0

reduce the fraction

x^2 - (4/4)(6/7) = 0

x^2 - (6/7) = 0

get the variable on one side, to solve

x^2 - (6/7) + (6/7) = 0 + (6/7)

x^2 = (6/7)

sqrt(x^2) = (+/-)sqrt(6/7)

x = +sqrt(6/7) or -sqrt(6/7)

so yes, you were correct.

but yeah, usually you do not want a denominator for a sqrt, so multiply by the sqrt(7/7) to get:

x = (+ or -) sqrt(42/49)

x = (+ or -) (1/7)*sqrt(42)

as for (24/26)^(3/4), yes that is (4throot(24/26))^3

you could take (24/26) and cube it, then take the 4th root

or you could take the 4th root and then cube it

same result.

and yes, it may be simpler to reduce (24/26) to (12/13) first before performing any operations to it.

(12/13) = (2*2*3/13)

(12/13)^3 = (12*12*12)/(13*13*13) = (2*2*2*2*2*2*3*3*3)/(13*13*13)

4throot((12/13)^3) = 4throot((2*2*2*2*2*2*3*3*3)/(13*13*13)) = 2*4throot((2*2*3*3*3)/(13*13*13))

multiply by 4throot(13*13*13/13*13*13)

[2/(13*13*13)]*4throot(2*2*3*3*3*13*13... = (2/2197)*4throot(237276)

Answer 2

Ok, since you keep getting stupid answers i'll help.

For the first one you are right, but you could simplify it more since you aren't really supposed to have a sqrt in the denominator. Just multiply the top and bottom by sqrt 7.

And for the second, you do the inside first. So it would be easier to simplify 24/26 to 12/13 and then do (12/13)^3 and then do the root4 for whatever answer you get.

Answer 3

for your first part of the question it is +-sqrt (6/7) and the second part of the question would be root4(216/343) due to you can cube both the denominator and numerator from 6/7... just wondering what math are you in due to the final answer of the second part coulbd be simplified to +-.8908