Some more algebra help please cant figure it out?

Question

1. if the side of a square are lengthen by 5 cm, the area becomes 121cm^2. what is the lenght of the oringinal square?

2. write a quardratic in the variable x having given numbers as solutions type the equation ax^2+bc+c=0 solution:1, only solution

3. rewrite with ratioanl exponent 3(20)

Answer 1

1)   square root of 121 is 11.  11 - 5 = 6

2)  x^2 - 2x + 1 = 0

3)  Not sure what you're asking.

Answer 2

(x+5)^2 = 121

x^2 + 10x + 25 = 121

x^2 + 10x -96 =

(x-6)(x+16) =0

x = 6

2. write a quadratic in the variable x having given numbers as solutions type the equation ax^2+bc+c=0 solution:1, only solution

x^2 + 4x +4 = 0  

1 solution, x = -2

3. rewrite with rational exponent 3(20)

15(2^2)

Answer 3

1.     sqrt of 121 is 11   so    11-5 is 6                  

6

Answer 4

1. (x+5)^2=121. Work out what x is

And as for 2 and 3, I'm not sure what you mean