Someone give me help on these 2 algebra questions?

Question

What is the midpoint of the segment joining (3, 5) and (-6, 11)?

What is the distance between the points (-7, 7) and (-4, 11)?

Answer 1

well, first you need to find the mid point for each number based on x's and y's

i.e. (x,y) and (1,2)   find the middle between x and 1

1)  X.  3+-6=-3

             -3/2=-1.5 for the x coordinate

     Y.  5+11=16

          16/2=8 for the y coordinate

repeat for number two,

the answer should be (-5.5, 9)

Answer 2

To find the midpoint of the segment, just take the average of the xs and the average of the ys:

Average of 3 and -6=(3+-6)/2=-3/2=-1.5

Average of 5 and 11=(5+11)/2=16/2=8

Midpoint is (-1.5,8)

distance=√[(x1-x2)²+(y1-y2)²]  

To find the distance, take the square root of the quantity (difference of the xs squared plus the difference of the ys squared)

difference of the x's: -7-(-4)=(-7+4)=3

difference of the xs squared:9

difference of the ys: (7-11)=-4

difference of the ys squared: 16

Sum of these: 9+16=25

Square root of the sum:5

The distance between the points is 5

_/

Answer 3

The midpoint of a segment with endpoints (x1 , y1) and (x2 , y2) has coordinates (x1+x2)/2 , (y1+y2)/2

So for your question, incorporate the points (3,5) and (-6,11) into the equation (x1+x2)/2 , (y1+y2)/2

x1 is the 3

x2 is the -6

y1 is the 5

y2 is the 11

Find the x coordinate:

(x1+x2)/2

(3+-6)/2

= -1.5

Find the y coordinate:

(y1+y2)/2

(5+11)/2

=8

Your answer is (-1.5,8)

For a clearer example, in case mine is confusing go to this website: http://regentsprep.org/Regents/math/midp...