Someone please help me with these math problems.?

Question

Solve:

5-sqrt(x) = 2

x = sqrt(x) - 6

x = 2x + 3

it's not that I can't do these problems, I just don't no If i'm doing it the right way, please help.

Answer 1

to solve a radical equation you need to get the radical alone so in the first one :

5 - root(x) = 2

subtract 5 from both sides this will give ya

- root(x) = -3

next raise each side to the power of the radical so in this case 2

this gives you -(x) = 9

next plug in the value for x 5-root(9)=2 and does it work square root of 9 is 3....5-3=2

second one is done the same way except you have to factor after you square both sides

third one subtract 2x from both sides gives ya -x=3 multiply both sides by -1 to get rid of the -x........x = -3 to check if its right just plug -3 in and do the arithmetic

Answer 2

sqrt(x) = 5-2

sqrt(x) = 3

x = 9

Answer 3

the first one, transfer sqrtx to the right and 2 to the left

5-2 = sqrt x

3 = sqrt x

9 =x

the second one, square both sides and simplify. after doing that, you have to square it again (with the sqrtx variable left in only one side) and simplify. long solution do it yourself

the third one is so easy!

x = -3

Answer 4

Here is the actual answer for the second one:

x = x^(1/2) - 6

(x + 6)^1 = x^(1/2)

(X+ 6)^(1*2) = x^(1/2 * 2)

(x + 6)^2 = x

x^2 + 12x + 36 = x

x^2 + 11x + 36 = 0

x^2 + 11x + (121/4) = -36+ (121/4)

(x + 5.5)^2 = -85/4

x= -5.5 + or - (sqrt(23))/4