Soybean meal is 16% protein;cornmeal is 8% protein .How many pounds of each should be mix together in order to

Question

get 320lb mixture that iss 9% protein?

Answer 1

Let X be the amount of soybean meal in pounds, Let Y be the amount of corn meal.

X + Y = 320

(X x 16 + Y x 8) /320 = 9

Solve the two equations for X and Y.

Answer 2

Let S be the weight of soybean

and C the weight of cornmeal

S + C = 320

(16S + .8C) / 320 = .9

Use substitution to solve, such as s = 320 - C.

Answer 3

you get it by solving the following equations. Lets say x is the amount of soybeans and y is cornmeal

0.16x + 0.08y = 0.09 * 320 (the amount of protein in both components has to equal the amount of protein in the final mix)

x + y = 320 (both components together weigh 320 lbs)

=> x = 320 - y

=> 0.16(320-y) + 0.08y = 28.8

51.2-0.16y+0.08y=28.8

-0.08y=-22.4

y=280

x=320-280 = 40

Answer: you need 40lbs soybeans and 280lbs cornmeal

Answer 4

what are you talking about?