Specific Heat Problem (Chemistry)

Question

A piece of unknown metal with mass 14.9 g is heated to 1000C and dropped into 75.0 g of water at 200C. The final temperature of the system is 28 degree Celsius. What is the specific heat of the metal?

Answer 1

i would like to change your water initial temp to 20.0 Celsius

and your initial metal temp to 100.0 Celsius

heat given to water:

dH = mCdT

dH = 75(4.184j/g-C)(8C)

dH = 2510.4 joules

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metal:

dH = mCdT

2510.4 = 14.9grams(C) (72 Celsius)

C = 2.34 Joules/g-C

Answer 2

Do you mean 100, 20? If so,

heat lost= heat gained = mass x change in T x sp heat in each case

14.9 x 72 x C = 75.0 x 8 x 4.184