Specific Heat Problem trouble!!!

Question

I'm having trouble with these calculations, could someone help me? Everytime I do it I get the wrong answer. Could someone walk me through the problem?

Observations

Mass of Fe metal: 100g

Volume of water in Calorimeter: 100mL

Mass of water in Calorimeter (use 1g per ml): 150g

Initial Temperature of metal: 20 C

Initial Temperature of water: 20 C

Final Temperature (both metal and water): 28 C

Determine the heat gained by the water:

Q water =

Q Fe =

Determine the specific heat of the metal:

C Fe = .11 cal/g C

Determine the atomic weight of your metal:

Look up the actual atomic weight on your periodic table. Determine your percent error using the equation.

Mass of Al metal: 100g

Volume of water in Calorimeter: 100mL

Mass of water in Calorimeter (use 1g per ml): 150g

Initial Temperature of metal: 20 C

Initial Temperature of water: 20 C

Final Temperature (both metal and water): 34 C

Determine the heat gained by the water:

Q water =

Q Al =

Determine the specific heat of the metal:

C Al =

Determine the atomic weight of your metal:

Look up the actual atomic weight on your periodic table. Determine your percent error using the equation

Answer 1

First problem (I think that the initial temperature of Fe must be wrong)

Heat gained by water = mass of water x temperature change of water x specific heat of water (4.184 J degree-1 g-1)

Heat lost by iron = mass of iron x temperature change of iron x specific heat of water (?? J degree-1 g-1)

Put these equal to each other, which they must be, to determine the value of ??

Other questions; use the rule of Dulong and Petit, which tells you the approximate specific heat PER MOLE of a metal.  Divide this by the specific heat per gram, and that will give you grams per mole, which is what you want.