Standard Form Algebra question?

Question

Could you help me with this question please? I'm really lost.

It says Write in standard from the equation of each line:

20. slope = 3;(1,5)

Answer 1

standard form means

y = mx + b

where m is the slope and b is the y intercept

They give you the slope, which 3.  They also give you one point on the line, which is (1,5).  You can substitute these values into the equation and solve for b:

5 = (3)(1) + b

b = 2

So the equation is

y = 3x + 2

Answer 2

You need to know 2 main equations:

Standard form: Ax + By = C (A B and C are just the numbers in front of the X's and Y's)

Point-slope form: Y - (Y-Coordinate) = Slope( X - (X-Coordinate))

You have to plug into the Point-slope formula first so you can convert it into standard form. So it will look like:

y - 5 = 3(x - 1)

Distribute the 3 on the right side of the equation:

y - 5 = 3x - 3

Subtract 3x to the other side:

-3x + y - 5 = -3

Add 5 to the other side:

-3x + y = 2 is the answer.

-EDIT- I think your teacher will like it better if the x wasn't negative so the better answer would be:

3x - y = -2

Cheers.