Question:

State the equation of the line in y=mx+b if the line...?

by  |  earlier

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is parallel to y=-x+4 and has a y-intercept of -3

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  1. If the line is in the form y = mx + b, then m is the slope and b the intercept.

    The slope of y = -x + 4 is -1

    parallel lines have the same slope so the new line also has a value for m of -1

    Since the intercept is -3, the linear equation is

    y = -x - 3


  2. x-3

  3. okay first you know it's the same slope so uses that.

                             -1=m

    Then use the point that is given (0,-3) and cross multiply using slope formula.

                             -1=(-3-y/ 0-x)

                              x=-3-y

                               y=-x-3

  4. here you need to apply the point slope for mula

    (y-y1)=m(x-x1)   the point of the equation is given by the y intercept which has a coordinate of (0, -3)

    also since the lines will be parallel is it known that they will have the same slope.

    so we have  y-(-3)=-1(x-0)

                        y+3=-x

                        y= -x-3

    notice both slopes are the same (-1)

  5. y=-x -3

    since the lines are parallel they have the same slope (or m value)

    so y = -x + B

    since the y intercept (or B value) is -3

    so

    y = -x+ (-3) or y = -x - 3

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