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Stoichiometry!?? pleaseee help i need this so badly?!?

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how many moles of ammonium ions are in 0.557 g of ammonium carbonate???

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  1. The molar mass of (NH4)2CO3 is 96 g/mol, so you have .00580 moles of ammonium carbonate, for each 1 mole of compound you have twice as many ammoniums, so you would have 0.0116 mol of ammonium ions.  


  2. Ammonium carbonate's formula is: (NH4)2CO3

    It's molar mass is: 96.09 g/mol

    The number of moles of Ammonium carbonate we have is: 0.557 g / 96.09 g/mol = X mol (do this with calculator)

    Then since there are 2 ammonium (NH4) ions in ammonium carbonate, the qty (moles) of ammonium you have is twice the result obtained earlier.

    Answer: 2 X

    (And please, begging is cute and all, but so unnecessary.)

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