Summer math packet. please help.?

Question

Given the point, P(6,0) and the line, l: 2x ? y = -2

A. find an equation for the line through P parallel to l.

B. Find an equation for the line through P perpendicular to l.

Please help and give a brief explanation. I'm not sure as to even how to start this problem.

Answer 1

A.

write the equation of the line in standard form

y = -2x - 2

where the slope = -2 (the coefficient of x)

the parallel line has the same slope

to find equation of second (parallel) line:

(y - 0)/(x - 6) = -2

y = -2(x - 6)

y = -2x + 12

B.

the slope of the perpendicular line is the negative reciprocal (-1/(-2)) = 1/2

(y - 0)/(x - 6) = 1/2

y = 1/2(x - 6)

y = x/2 - 3