Suppose a rocket burned 4500 pounds of hydrogen to go into space...?

Question

From my class for homework, I'm confused by how much oxygen there should be. Suppose a rocket burned 4500 pounds of hydrogen to go into space. If all of this hydrogen combined with oxygen during the combustion, how many pounds of water would be produced?

Answer 1

H2 = Hydrogen

O2 = Oxygen

Balanced Reaction =

2H2 + O2 -> 2H2O

4500lb hydrogen

1lb=453.6g

1kg=1000kg

4500lb = 2041200g H2

1 mole H2 = 2.01g

(2041200g H2) * 1mole/2.01g = (1015522moles H2)

(1015522moles H2) * (2moles H2/ 2moles H2O)

=1015522 moles H2O

1L H2O =

1 mole H2O = 18.01g

(1015522moles H2O) * (18.01g/1mole H2O)

=18289551 grams H2O

(18289551 g H2O) * (1lb/453.6 g) = 40321lb H2O

Round off S.D. to get 40320lb H2O